(X^2+25x-25)=0

Solution for (X^2+25x-25)=0 equation:

(X^2+25X-25)=0

We get rid of parentheses

X^2+25X-25=0

a = 1; b = 25; c = -25;
Δ = b2-4ac
Δ = 252-4·1·(-25)
Δ = 725
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{725}=\sqrt{25*29}=\sqrt{25}*\sqrt{29}=5\sqrt{29}$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(25)-5\sqrt{29}}{2*1}=\frac{-25-5\sqrt{29}}{2}
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(25)+5\sqrt{29}}{2*1}=\frac{-25+5\sqrt{29}}{2}
$